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25/01/2022 2:22 pm
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The enol form of acetone after treatment with D2O gives:
(a) \(CH_3- \overset{OD}{\overset{|}{C}}=CH_2\)
(b) \(CH_3- \overset{O}{\overset{||}{C}}-CD_3\)
(c) \(CH_2=\overset{OH}{\overset{|}{C}}-CH_2D\)
(d) \(CD_2= \overset{OD}{\overset{|}{C}}-CD_3\)
1 Answer
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25/01/2022 2:25 pm
Correct answer: (a)
Explanation:
The enol form of acetone is
\(CH_3- \overset{OH}{\overset{|}{C}}=CH_2\) with D2O it gives
\(CH_3- \overset{OD}{\overset{|}{C}}=CH_2\)