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26/01/2022 5:33 pm
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1.4 kg of an organic compound was digested according to Kjeldahl’s method and the ammonia evolved was absorbed in 60 mL of M/10 H2SO4 solution. The excess sulphuric acid required 20 mL of M/10 NaOH solution for neutralization. The percentage of nitrogen in the compound is:
(a) 10
(b) 3
(c) 24
(d) 5
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26/01/2022 5:41 pm
Correct answer: (a) 10
Explanation:
Milli equivalents of H2SO4
= 60 x \(\frac{M \times 2}{10}\) = 12
Milli equivalents of NaOH = 20 x \(\frac{M}{10}\) = 2
Milli equivalent of NH3 = 12 - 2 = 10
% of nitrogen = \(\frac{1.4 \times (N \times V)NH_3}{(Wt.\; of\;organic\; compound}\)
= \(\frac{1.4 \times 10}{1.4}\) = 10