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30/09/2020 10:34 am
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KMnO4 reacts with oxalic acid according to the equation:
2MnO-4 + 5C2O-4 + 16H+ → 2Mn++ + 10CO2 + 8H2O
Here 20 mL of 0.1 M KMnO4 is equivalent to:
(a) 20 mL of 0.5 M H2C2O4
(b) 50 mL of 0.5 M H2C2O4
(c) 50 mL of 0.1 M H2C2O4
(d) 20 mL of 0.1 M H2C2O4
1 Answer
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30/09/2020 10:39 am
(c) 50 mL of 0.1 M H2C2O4
Explanation:
Meq of A = Meq of B.
0.1 M KMnO4 = 0.5 N KMnO4
∴ Meq of KMnO4 = 20 × 0.5 = 10 (n factor = 5)
Meq of 50 ml of 0.1 M H2C2O4 = 50 × 0.2 = 10
(0.1 M H2C2O4 = 0.2 N H2C2O4)