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60 gm of an organic compound on analysis is found to have C = 24 g, H = 4 g and O = 32 g.

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60 gm of an organic compound on analysis is found to have C = 24 g, H = 4 g and O = 32 g. The empirical formula of compound is:

(a) CH2O

(b) CHO

(c) C2H2O

(d) C2H2O2

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(a) CH2O

Explanation:

Ratio of no. of atoms = 24/12 : 4/1 : 32/16

= 2 : 4 : 2 = 1 : 2 : 1

Empirical formula = CH2O.

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