Notifications
Clear all
10^21 molecules are removed from 200 mg of CO2. The moles of CO2 left are :
0
29/09/2020 4:21 pm
Topic starter
1021 molecules are removed from 200 mg of CO2. The moles of CO2 left are :
(a) 2.88 x 10-3
(b) 28.8 x 10-3
(c) 288 x 10-3
(d) 28.8 x 103
Answer
Add a comment
Add a comment
Topic Tags
1 Answer
0
29/09/2020 4:25 pm
(a) 2.88 x 10-3
Explanation:
No. of moles = Wt. in g/Mol. wt
No. of moles in 200 mg = 200/1000 x 44
= 4.5 x 10-3 moles
No. of moles in 1021 molecules
= 1021/ 6.02 x 1023 = 1.67 x 10-3 moles
No. of moles left = (4.5 – 1.67) × 10-3
= 2.88 x 10-3
Add a comment
Add a comment
Forum Jump:
Related Topics
-
Assertion: Equal moles of different substances contain same number of constituent particles.
4 years ago
-
Assertion: The normality of 0.3 M aqueous solution of H3PO3 is equal to 0.6 N.
4 years ago
-
Assertion: One molal aqueous solution of glucose contains 180g of glucose in 1 kg water.
4 years ago
-
Assertion: Equivalent weight of a base = Molecular weight/Acidity
4 years ago
-
Assertion: Atoms can neither be created nor destroyed.
4 years ago
Forum Information
- 321 Forums
- 27.3 K Topics
- 53.8 K Posts
- 0 Online
- 12.4 K Members
Our newest member: Stripchat
Forum Icons:
Forum contains no unread posts
Forum contains unread posts
Topic Icons:
Not Replied
Replied
Active
Hot
Sticky
Unapproved
Solved
Private
Closed