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29/09/2020 4:10 pm
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0.4 moles of HCl and 0.2 moles of CaCl2 were dissolved in water to have 500 mL of solution, the molarity of Cl- ion is:
(a) 0.8 M
(b) 1.6 M
(c) 1.2 M
(d) 10.0 M
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29/09/2020 4:17 pm
(b) 1.6 M
Explanation:
HCl(0.4 moles) ⇌ H+ + Cl-
CaCl2(0.2 moles) ⇌ Ca2+ + 2Cl-(2 x 0.2 = 0.4 moles)
Total Cl- moles = 0.4 + 0.4 = 0.8 moles
Molarity = Moles/Vol. in L
∴ Molarity of Cl- = 0.8/0.5 = 1.6 M