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When burnt in air, 14.0 g mixture of carbon and sulphur gives a mixture of CO2 and SO2 in the volume ratio of 2:1

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When burnt in air, 14.0 g mixture of carbon and sulphur gives a mixture of CO2 and SO2 in the volume ratio of 2:1, volume being measured at the same conditions of temperature and pressure moles of carbon in the mixture is

(a) 0.75

(b) 0.5

(c) 0.40

(d) 0.25

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Correct answer: (b) 0.5

Explanation:

Let weight of C be x g, then S will be (14 – x)g

\(\frac{\frac{x}{12}}{\frac{(14-x)}{32}}\) = \(\frac{2}{1}\)

∴ x = 6 g; Moles of C = \(\frac{6}{12}\) = 0.5

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