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Some Basic Concepts of Chemistry
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12/08/2021 11:41 am
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What is the molarity of SO42- ion in aqueous solution that contains 34.2 ppm of Al2(SO4)3? (Assume complete dissociation and density of solution 1g/mL)
(a) 3 × 10-4 M
(b) 2 × 10-4 M
(c) 10-4 M
(d) None of these
1 Answer
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12/08/2021 11:50 am
(a) 3 × 10-4 M
Explanation:
We know that
= \(\frac{mass\;of\;Al_2(SO_4)_3}{mass\;of\;water}\times 10^6\)
= 34.2 mg molarity of Al2(SO4)3
= \(\frac{34.2 \times 10^{-3}}{342}\)M
= 10-4 M
Al2(SO4)3(aq) → 2Al3+(aq) + 3SO42-(aq)
10-4 M 2 x 10-4 M 3 x 10-4 M
[SO42-] = 3 × 10-4 M
This post was modified 3 years ago 2 times by admin