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What is the empirical formula of vanadium oxide, if 2.74 g of the metal oxide contains 1.53 g of metal?

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What is the empirical formula of vanadium oxide, if 2.74 g of the metal oxide contains 1.53 g of metal?

(a) V2O3

(b) VO

(c) V2O5

(d) V2O7

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Correct answer: (c) V2O5

Explanation:

Mass of oxide = Mass of metal + Mass of oxygen

2.74 + 1.53 + WOxygen ⇒ WOxygen = 1.21 g

Moles of V = \(\frac{1.53}{51}\) = 0.03

Moles of O = \(\frac{1.21}{16}\) = 0.075

V0.03O0.075

VO2.5 ⇒ V2O5

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