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The percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (atomic weight = 78.4). Then minimum molecular weight of peroxidase anhydrous enzyme is

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The percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (atomic weight = 78.4). Then minimum molecular weight of peroxidase anhydrous enzyme is

(a) 1.568 × 103

(b) 1.568 × 104

(c) 15.68

(d) 3.136 × 104 

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Answer is: (b) 1.568 × 104

Explanation:

0.5% by weight means if Mol. wt. is 100 then mass of Se is 0.5. If at least one atom of Se is present in the molecule then

M. Wt = \(\frac{100}{0.5}\)x 78.4

= 1.568 × 104

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