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Some Basic Concepts of Chemistry
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14/08/2021 10:40 am
Topic starter
The mass of BaCO3 produced when excess CO2 is bubbled through a solution of 0.205 mol Ba(OH)2 is:
(a) 81 g
(b) 40.5 g
(c) 20.25 g
(d) 162 g
1 Answer
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14/08/2021 10:45 am
Topic starter
Correct answer: (b) 40.5 g
Explanation:
Ba(OH)2 + CO2 → BaCO3 + H2O
1 mol 1 mol
1 mol Ba(OH)2 = 0.205 mol BaCO3
Wt. of substance = No. of moles x Molecular mass
= 0.205 x 197.3 = 40.5 g