Notifications
Clear all
Some Basic Concepts of Chemistry
1
Posts
2
Users
0
Likes
297
Views
0
12/08/2021 9:38 am
Topic starter
The impure 6 g of NaCl is dissolved in water and then treated with excess of silver nitrate solution. The mass of precipitate of silver chloride is found to be 14 g. The % purity of NaCl solution would be:
(a) 95%
(b) 85%
(c) 75%
(d) 65%
1 Answer
0
12/08/2021 9:45 am
Correct answer: (a) 95%
Explanation:
The reaction that takes place is
NaCl + AgNO3 → AgCl↓ + NaNO3
∴ 143.5 g of AgCl is produced from 58.5 g NaCl
∴ 14 g of AgCl will be produced from
\(\frac{58.5 \times 14}{143.5}\) = 5.70g NaCl
This is the amount of NaCl in common salt;
% purity = \(\frac{5.70}{6}\)x 100 = 95%