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The amount of zinc required to produce 224 mL of H2 at STP on treatment with dil. H2SO4 will be

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The amount of zinc required to produce 224 mL of H2 at STP on treatment with dil. H2SO4 will be

(a) 6.5 g

(b) 0.65 g

(c) 65 g

(d) 0.065 g

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Answer is: (b) 0.65 g

Explanation:

Zn + H2SO4 → ZnSO4 + H2

65 g Zn gives 1 mole of H2 = 22400 mL of H2 224 mL of H2 will be obtained from 0.65 g Zn.

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