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Some Basic Concepts of Chemistry
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14/08/2021 11:08 am
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If potassium chlorate is 80% pure, then 48 g of oxygen would be produced from (atomic mass of K = 39)
(a) 153.12 g of KClO3
(b) 122.5 g of KClO3
(c) 245 g of KClO3
(d) 98 g of KClO3
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14/08/2021 11:14 am
Topic starter
Correct answer: (a) 153.12 g of KClO3
Explanation:
2KClO3 \(\overset{heat}\longrightarrow\) 2KCl + 3O2
2 x 122.5g 3 x 32g
48g of oxygen will be produced from 122.5g of KClO3
∴ Amount of 80% KClO3 needed
= \(\frac{100}{80}\) x 122.5 =153.12g