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Some Basic Concepts of Chemistry
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10/08/2021 11:50 am
Topic starter
If 3.01 × 1020 molecules are removed from 98 mg of H2SO4, then the number of moles of H2SO4 left are
(a) 0.1 × 10–3
(b) 0.5 × 10–3
(c) 1.66 × 10–3
(d) 9.95 × 10–2
1 Answer
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10/08/2021 11:54 am
Answer is: (b) 0.5 × 10–3
Explanation:
Moles of H2SO4 in 98 mg of H2SO4
= \(\frac{1}{98}\)x 0.098 = 0.001
Moles of H2SO4 removes
= \(\frac{3.01 \times 10^{20}}{6.02 \times 10^{23}}\)
= 0.5 x 10–3 = 0.0005
Moles of H2SO4 left
= 0.001 – 0.0005 = 0.5 × 10–3