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If 224 mL of a triatomic gas has a mass of 1 g at 273K and 1 atmospheric pressure then the mass of one atom is

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If 224 mL of a triatomic gas has a mass of 1 g at 273K and 1 atmospheric pressure then the mass of one atom is

(a) 8.30 × 10-23 g

(b) 2.08 × 10-23 g

(c) 5.53 × 10-23 g

(d) 6.24 × 10-23 g

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Correct answer: (c) 5.53 × 10-23 g

Explanation:

The conditions given are standard conditions 224 mL has mass = 1g ; 22400 mL will have mass = 100g.

This is mol. wt of gas 6.023 × 1023 molecules have 3 × 6.023 × 1023 atoms since gas is triatomic

∴ weight of one atom

= \(\frac{100}{3 \times 6.023 \times 10^{23}}\)

= 5.53 × 10-23 g

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