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How many moles of P4 can be produced by reaction of 0.10 moles Ca5(PO4)3F, 0.36 moles SiO2 and 0.90 moles C according to the following reaction?
Some Basic Concepts of Chemistry
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13/08/2021 10:20 am
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How many moles of P4 can be produced by reaction of 0.10 moles Ca5(PO4)3F, 0.36 moles SiO2 and 0.90 moles C according to the following reaction?
4Ca5(PO4)3F + 18SiO2 + 30C → 3P4 + 2CaF2 + 18CaSiO3 + 30CO
(a) 0.060
(b) 0.030
(c) 0.045
(d) 0.075
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13/08/2021 10:24 am
Correct answer: (a) 0.060
Explanation:
0.1 0.36 0.9
4Ca5(PO4)3F + 18SiO2 + 30C → 3P4 + 2CaF2 + 18CaSiO3 + 30CO
18 moles of SiO2 gives 3 moles of P4 0.36 moles of SiO2 will give
= \(\frac{3}{18} \times 0.36\)
= 0.06 mole
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