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How many moles of P4 can be produced by reaction of 0.10 moles Ca5(PO4)3F, 0.36 moles SiO2 and 0.90 moles C according to the following reaction?

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How many moles of P4 can be produced by reaction of 0.10 moles Ca5(PO4)3F, 0.36 moles SiO2 and 0.90 moles C according to the following reaction?

4Ca5(PO4)3F + 18SiO2 + 30C → 3P4 + 2CaF2 + 18CaSiO3 + 30CO

(a) 0.060

(b) 0.030

(c) 0.045

(d) 0.075

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Correct answer: (a) 0.060

Explanation:

0.1                      0.36         0.9

4Ca5(PO4)3F + 18SiO2 + 30C → 3P4 + 2CaF2 + 18CaSiO3 + 30CO

18 moles of SiO2 gives 3 moles of P4 0.36 moles of SiO2 will give

= \(\frac{3}{18} \times 0.36\)

= 0.06 mole

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