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Some Basic Concepts of Chemistry
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10/08/2021 11:37 am
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Dissolving 120 g of a compound of mol. wt. 60 in 1000 g of water gave a solution of density 1.12 g/ mL. The molarity of the solution is:
(a) 1.00 M
(b) 2.00 M
(c) 2.50 M
(d) 4.00 M
1 Answer
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10/08/2021 11:42 am
Answer is: (b) 2.00 M
Explanation:
Given
mass of solute (w) = 120 g
mass of solvent (w) = 1000 g
Mol. mass of solute = 60 g
density of solution = 1.12 g/ mL
From the given data,
Mass of solution = 1000 + 120 = 1120 g
d = \(\frac{Mol.\;mass}{V}\) or
V = \(\frac{Mol.\;mass}{d}\)
Volume of solution V = \(\frac{1120}{1.12}\)
= 1000mL
or = 1 litre
Now molarity (M) = \(\frac{W}{Mol.\; mass \times V(lit)}\)
= \(\frac{120}{60 \times 1}\)
= 2M