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A transition metal M forms a volatile chloride which has a vapour density of 94.8. If it contains 74.75% of chlorine the formula of the metal chloride will be

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A transition metal M forms a volatile chloride which has a vapour density of 94.8. If it contains 74.75% of chlorine the formula of the metal chloride will be

(a) MCl3

(b) MCl2

(c) MCl4

(d) MCl5

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Correct answer: (c) MCl4

Explanation:

74.75% of chlorine means 74.75g chlorine is present in 100g of metal chloride.

Weight of metal = 100g – 74.75g

= 25.25g

Equivalent weight

= \(\frac{weight\;of\;metal}{weight\;of\;chlorine}\) x 35.5

= \(\frac{25.25}{74.75}\) x 35.5 = 12

Valency of metal

= \(\frac{2 \times V.D.}{Equivalent\;wt. of\;metal + 35.5}\)

= \(\frac{2 \times 94.8}{12 + 35.5}\) = 4

∴ Formula of compound = MCl4

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