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Some Basic Concepts of Chemistry
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10/08/2021 11:43 am
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A mixture of O2 and gas "Y" mol. mass 80 in the mole ratio a : b has a mean molecular mass 40. What would be mean molecular mass, if the gases are mixed in the ratio b : a under, identical conditions? (Assume that gases are non-reacting):
(a) 40
(b) 48
(c) 62
(d) 72
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10/08/2021 11:48 am
Answer is: (d) 72
Explanation:
Let mole fraction of O2 is x
40 = 32 × x + 80 (1 – x)
or x = \(\frac{5}{6}\)
a : b = x : (1 - x) = \(\frac{5}{6}\):\(\frac{1}{6}\)
When ratio is changed
Mmixture = 32 x \(\frac{1}{60}\) + 80 x \(\frac{5}{6}\)
= 72