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A compound contains 54.55 % carbon, 9.09% hydrogen, 36.36% oxygen. The empirical formula of this compound is:

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A compound contains 54.55 % carbon, 9.09% hydrogen, 36.36% oxygen. The empirical formula of this compound is:

(a) C3H5O

(b) C4H8O2

(c) C2H4O2

(d) C2H4O

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Correct answer: (d) C2H4O

Explanation:

C 54.55   54.55/12 = 4.5

4.5/2.27 = 2

H 9.09  9.09/1 = 9.09 

9.09/2.27 = 4

O 36.36   36.36/16 = 2.27

2.27/2.27= 1

Hence empirical formula of the compound = C2H4O

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