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5 g of benzene on nitration gave 6.6 g of nitrobenzene. The theoretical yield of the nitrobenzene will be

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5 g of benzene on nitration gave 6.6 g of nitrobenzene. The theoretical yield of the nitrobenzene will be

(a) 4.5 g

(b) 5.6 g

(c) 8.09 g

(d) 6.6 g

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Correct answer: (c) 8.09 g

Explanation:

C6H6 + HNO3 → C2H5NO6 + H2O

78g                     123g

Now since 78g of benzene on nitration give = 123g nitrobenzene

hence 5g of benzene on nitration give

= \(\frac{123}{78}\) x 5 = 7.88g

nearest answer is (c) i.e. theoretical yield = 7.88 g

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