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Some Basic Concepts of Chemistry
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13/08/2021 11:40 am
Topic starter
2 g of a mixture of CO and CO2 on reaction with excess I2O5 produced 2.54 g of 2I. What will be the mass % of CO2 in the original mixture?
(a) 35
(b) 70
(c) 30
(d) 60
1 Answer
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13/08/2021 11:45 am
Correct answer: (c) 30
Explanation:
5CO + I2O5 → 5CO2 + I2
Mole of I2O5 = \(\frac{25.4}{254}\)
= 0.01 = 0.05 moles of CO
Weight of CO 0.05 x 28 = 1.4 g
Weight of CO2 = 2- 1.4 = 0.6 g
Hence % of CO2 = \(\frac{0.6}{2}\) x 100
= 30%