Forum

2 g of a mixture of...
 
Notifications
Clear all

2 g of a mixture of CO and CO2 on reaction with excess I2O5 produced 2.54 g of 2I. What will be the mass % of CO2 in the original mixture?

1 Posts
2 Users
0 Likes
408 Views
0
Topic starter

2 g of a mixture of CO and CO2 on reaction with excess I2O5 produced 2.54 g of 2I. What will be the mass % of CO2 in the original mixture?

(a) 35

(b) 70

(c) 30

(d) 60

1 Answer
0

Correct answer: (c) 30

Explanation:

5CO + I2O5 → 5CO2 + I2

Mole of I2O5 = \(\frac{25.4}{254}\)

= 0.01 = 0.05 moles of CO

Weight of CO 0.05 x 28 = 1.4 g

Weight of CO2 = 2- 1.4 = 0.6 g

Hence % of CO2 = \(\frac{0.6}{2}\) x 100

= 30%

Share:

How Can We Help?