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100 cm^3 of 0.1 N HCl is mixed with 100 cm^3 of 0.2 N NaOH solution. The resulting solution is

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100 cm3 of 0.1 N HCl is mixed with 100 cm3 of 0.2 N NaOH solution. The resulting solution is

(a) 0.1 N and the solution is basic

(b) 0.1 N and the solution is acidic

(c) 0.05 N and the solution is basic

(d) 0.05 N and the solution is acidic

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Correct answer: (c) 0.05 N and the solution is basic

Explanation:

Normality

= \(\frac{N_1V_1 - N_2V_2}{V_1 + V_2}\)

= \(\frac{0.2 \times 100 - 0.1 \times 100}{100 + 100}\)

= \(\frac{10}{200}\) = 0.05N NaOH

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