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Some Basic Concepts of Chemistry
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14/08/2021 10:12 am
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10 moles SO2 and 15 moles O2 were allowed to react over a suitable catalyst. 8 moles of SO3 were formed. The remaining moles of SO2 and O2 respectively are
(a) 2 moles, 11 moles
(b) 2 moles, 8 moles
(c) 4 moles, 5 moles
(d) 8 moles, 2 moles
1 Answer
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14/08/2021 10:16 am
Correct answer: (a) 2 moles, 11 moles
Explanation:
2SO2 + O2 → 2SO3
10 15 0
10-2x 15-x 2x
∵ 2x = 8 x = 4
Hence, remaining, SO2 = 10 - 8 = 2 moles,
O2 = 15 - 4 = 11 moles