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10 mL of 2 M NaOH solution is added to 200 mL of 0.5 M of NaOH solution. What is the final concentration? (a) 0.57 M (b) 5.7 M (c) 11.4 M (d) 1.14 M

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10 mL of 2 M NaOH solution is added to 200 mL of 0.5 M of NaOH solution. What is the final concentration?

(a) 0.57 M

(b) 5.7 M

(c) 11.4 M

(d) 1.14 M

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Correct answer: (a) 0.57 M

Explanation:

From molarity equation

\(M_1V_1 + M_2V_2\) = MV(total)

2 x \(\frac{10}{1000}\) + 0.5 x \(\frac{200}{1000}\) = M x \(\frac{210}{1000}\)

120 = M x 210

M = \(\frac{120}{210}\) = 0.57 M

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