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Some Basic Concepts of Chemistry
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13/08/2021 10:30 am
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1 mole of mixture of CO and CO2 requires exactly 28 g KOH in solution for complete conversion of all the CO2 into K2CO3. How much amount more of KOH will be required for conversion into K2CO3. If one mole of mixture is completely oxidized to CO2
(a) 112 g
(b) 84 g
(c) 56 g
(d) 28 g
1 Answer
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13/08/2021 10:34 am
Correct answer: (b) 84 g
Explanation:
CO + \(\frac{1}{2}\)O2 → CO2
CO2 + KOH → K2CO3 + H2O
Moles of KOH = \(\frac{28}{56}\) = 0.50
It corresponds to 0.25 mol of CO2
Hence mol of CO = 1 – 0.25 = 0.75
= mole of CO2 formed
Mol of KOH required = 2 × 0.75 = 1.5
= 1.5 × 56 = 84 g