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Some Basic Concepts of Chemistry
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14/08/2021 10:55 am
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1 g mixture of equal number of mole of Li2CO3 and other metal carbonates (M2CO3) required 21.6 mL of 0.5N HCl for complete neutralisation reaction. What is the approximate atomic mass of the other metal?
(a) 25
(b) 23
(c) 51
(d) 118
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14/08/2021 10:59 am
Topic starter
Correct answer: (d) 118
Explanation:
Let x g of Li2CO3 and (1 - x) g of M2CO3 present in given mixture
2 × Total moles of carbonates = moles of HCl and
2 x \((\frac{x}{74} + \frac{1 - x}{2M + 60})\) = 21.6 x 0.5 x 10-3
x = 0.20
∵ \(\frac{x}{74}\) = \(\frac{1 - x}{2M + 60}\)
M = 118