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Some Basic Concepts of Chemistry
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13/08/2021 11:14 am
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1.575 g of oxalic acid (COOH)2.xH2O are dissolved in water and the volume made upto 250 mL. On titration 16.68 mL of this solution requires 25 mL of N/15 NaOH solution for complete neutralization, calculate x.
(a) 3
(b) 2
(c) 4
(d) 5
1 Answer
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13/08/2021 11:19 am
Correct answer: (b) 2
Explanation:
Meq of oxalic acid in 16.68 ml = Meq of NaOH
= 25 x \(\frac{1}{15}\)
Meq of oxalic acid in 250 ml
= 25 x \(\frac{1}{15}\) x \(\frac{250}{16.68}\) = 24.98
\(\frac{1.575}{\frac{(90 + 18x)}{2}}\) x 1000 = 24.98
∴ x = 2