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Some Basic Concepts of Chemistry
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12/08/2021 12:37 pm
Topic starter
1.12 mL of gas is produced at S.T.P. by the action of 4.12 mg of alcohol ROH with methyl magnesium Iodide. The molecular mass of alcohol is
(a) 16.0
(b) 41.2
(c) 82.4
(d) 156.0
1 Answer
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12/08/2021 12:41 pm
Correct answer: (c) 82.4
Explanation:
Let the alcohol be ROH and x its molecular weight
ROH + CH3MgI → CH4 + ROMgI
xg 16g
\(\frac{4.12}{1000}\)g of methane
Methane actually obtained is = \(\frac{16 \times 1.12}{22400}\)g
∴ \(\frac{16 \times 4.12}{x \times 1000}\) = \(\frac{16 \times 1.12}{22400}\)g
⇒ x = 82.4