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The vapour pressure of pure benzene at a certain temperature is 0.850 bar.

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The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non-volatile, nonelectrolyte solid weighing 0.5 g is added to 39.0 g of benzene (molar mass 78 g/mol). The vapour pressure of the solution then is 0.845 bar. What is the molecular mass of the solid substance?

(a) 58

(b) 180

(c) 170

(d) 145

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(c) 170

Explanation:

benzene = 0.850 bar; Wbenzene = 39.0g

M.W. = 78 g/mol

solution = 0.845 bar; w = 0.5 g

Let n be the no. of moles of non volatile solid; w and m be the weight of solid and molecular mass respectively.

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