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01/10/2020 5:28 pm
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On mixing 3 g of non - volatile solute in 200 mL of water, its boiling point (100°C) becomes 100.52°C. If Kb for water is 0.6 K/m then molecular wt. of solute is :
(a) 10.5 g mol-1
(b) 12.6 g mol-1
(c) 15.7 g mol-1
(d) 17.3 g mol-1
1 Answer
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01/10/2020 5:30 pm
(d) 17.3 g mol-1
Explanation:
ΔT = Kb w/m x 1000/W
0.52 = 0.6 x 3/m x 1000/200
m = 1.8 x 5/0.52 = 17.3 g mol-1