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02/10/2020 10:49 am
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At a particular temperature, the vapour pressures of two liquids A and B are respectively 120 and 180 mm of mercury. If 2 moles of A and 3 moles of B are mixed to form an ideal solution, the vapour pressure of the solution at the same temperature will be (in mm of mercury)
(a) 156
(b) 145
(c) 150
(d) 108
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02/10/2020 10:54 am
(a) 156
Explanation:
Vapour pressure of solution = PA + PB
= P°AXA + P°BXB = (120 x 2)/5 + (180 x 3)/5
= 156 mm Hg