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01/10/2020 8:35 pm
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A 5% solution (by mass) of cane sugar in water has freezing point of 271 K and freezing point of pure water is 273.15 K. The freezing point of a 5% solution (by mass) of glucose in water is
(a) 271 K
(b) 273.15K
(c) 269.07 K
(d) 277.23 K
1 Answer
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01/10/2020 8:38 pm
(c) 269.07 K
Explanation:
From the relation
So, freezing point of glucose solution
= 273.15 – 4.085
= 269.07 K