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01/10/2020 8:51 pm
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0.01 M solution of KCl and BaCl2 are prepared in water. The freezing point of KCl is found to be –2°C. What is the freezing point of BaCl2 to be completely ionised?
(a) – 3°C
(b) + 3°C
(c) – 2°C
(d) – 4°C
1 Answer
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01/10/2020 8:58 pm
(a) -3°C
Explanation:
ΔTf ∝ i
∴ ΔTf for KCl/ ΔTf for BaCl2 = i for KCl/i for BaCl2
∴ ΔTf for KCl/ ΔTf for BaCl2 = 2/3 (∴ ΔTf for KCl = 2)
ΔTf for BaCl2 = (3 x 2)/3 = 3
∴ Freezing point of BaCl2 = -3°C