Notifications
Clear all
Redox Reactions
1
Posts
2
Users
0
Likes
1,832
Views
0
14/11/2021 10:48 am
Topic starter
Which of the following is correct code for x and y in the following reaction.
2Na(s) + S(s) → Na2S(s)
Na (x) → Na2
S (y) → S
(i) x = oxidation reaction, y = reduction reaction
(ii) x = gain of two electrons, y = loss of two electrons,
(iii) x = reduction reaction, y = oxidation reaction
(iv) x = loss of two electrons, y = gain of two electrons
(a) (i) and (ii)
(b) (i) and (iv)
(c) (ii) and (iii)
(d) (iii) and (iv)
1 Answer
0
14/11/2021 10:51 am
Correct answer: (b) (i) and (iv)
Explanation:
Oxidation reaction (loss of 2e–)
2Na(s) + S(s) → Na2S(s)
Na (x) → Na2 Oxidation reaction (loss of 2e–)
S (y) → S (Reduction reaction (gain of 2e–)