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The oxidation state of nitrogen is correctly given for Compound - Oxidation state (a) [Co(NH3)5Cl]Cl2 → 0

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The oxidation state of nitrogen is correctly given for

Compound     -      Oxidation state

(a) [Co(NH3)5Cl]Cl2 → 0

(b) NH2OH  →  -2

(c) (N2H5)2SO4 → +2

(d) Mg3N2  → –3

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Correct answer: (d) Mg3N2  → –3

Explanation:

(a) \([\overset{+}{Co}(\overset{0}{NH_3})_5\overset{-1}{Cl}]^{+2}\overset{-1 \times 2}{Cl_2}\)

+3 + 5x + 15 - 1 = +2

5x + 17 = +2

5x = -15

x = –3;

Oxidation State of N = -3

(b) NH2OH : x + 3 - 2 = 0 

x = -1 Oxidation state of N = -1

(c) (N2H5)+1SO42+

N2H5+: 2x + 5 = +1 

x = -2

Oxidation number of N = -2

(d) Mg3N2: 2 × 3 + 2x = 0

2x = –6

x = –3

Oxidation state of N = –3

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