The oxidation number of phosphorus in Ba(H2PO2)2 is (a) +3 (b) +2 (c) +1 (d) -1

Correct answer: (c) +1 Explanation: Ba2+(H2PO2)2-1x2 H2PO2-: 2 + x - 4 = -1 ⇒ x = +1 ∴ Oxidation state of P = +1

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The oxidation number of phosphorus in Ba(H2PO2)2 is

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Last Post by Reyana09 3 years ago

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17/11/2021 11:47 am

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Palak23

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The oxidation number of phosphorus in Ba(H₂PO₂)₂ is

(a) +3

(b) +2

(d) -1

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17/11/2021 11:59 am

Reyana09

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Correct answer: (c) +1

Explanation:

Ba²⁺(H₂PO₂)₂^-1x2

H₂PO₂^-: 2 + x - 4 = -1

⇒ x = +1

∴ Oxidation state of P = +1

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