Notifications
Clear all
1
18/11/2021 11:44 am
Topic starter
The number of electrons involved in the reduction of one nitrate ion to hydrazine is
(a) 8
(b) 5
(c) 3
(d) 7
1 Answer
1
18/11/2021 2:34 pm
Correct answer: (d) 7
Explanation:
\(\overset{+5}{N}O_3^- \) → \(\overset{-2}{N_2}H_4 \)
So, for reduction of 1 mole of NO3- number of electrons required is 7.