The correct decreasing order of oxidation number of oxygen in compounds BaO2, O3, KO2 and OF2 is (a) BaO2 > KO2 > O3 > OF2 (b) OF2 > O3 > KO2 > BaO2 (c) KO2 > OF2 > O3 > BaO2 (d) BaO2 > O3 > OF2 > KO2

Correct answer: (b) OF2 > O3 > KO2 > BaO2 Explanation: Oxidation no. of O are + 2, 0, -[latex]rac{1}{2}[/latex] and -1 respectively.

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The correct decreasing order of oxidation number of oxygen in compounds BaO2, O3, KO2 and OF2 is

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17/11/2021 11:13 am

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Palak23

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The correct decreasing order of oxidation number of oxygen in compounds BaO₂, O₃, KO₂ and OF₂ is

(a) BaO₂ > KO₂ > O₃ > OF₂

(b) OF₂ > O₃ > KO₂ > BaO₂

(d) BaO₂ > O₃ > OF₂ > KO₂

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17/11/2021 11:16 am

Reyana09

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Correct answer: (b) OF₂ > O₃ > KO₂ > BaO₂

Explanation:

Oxidation no. of O are + 2, 0, -\(\frac{1}{2}\) and -1 respectively.

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