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18/11/2021 10:57 am
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In which of the following pairs is there the greatest difference in the oxidation numbers of the underlined elements?
(a) \(\underline{N}O_2\) and \(\underline{N_2}O_4\)
(b) \(\underline{P_2}O_5\) and \(\underline{P_4}O_{10}\)
(c) \(\underline{N_2}O\) and \(\underline{N}O\)
(d) \(\underline{S}O_2\) and \(\underline{S}O_3\)
1 Answer
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18/11/2021 11:01 am
Correct answer: (d) \(\underline{S}O_2\) and \(\underline{S}O_3\)
Explanation:
O.N. of N in NO2 and N2O4 is +4
difference is zero.
O.N. of P in P2O5 and P4O10 is +5
difference is zero
O.N. of N in N2O is +1 and in NO is +2. The difference is 1
O.N. of S in SO2 is +4 and in SO3 is +6. The difference is +2.