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In the reaction Cr2O7^2- + 14H^+ + 6I^- → 2Cr^3+ + 7H2O + 3I2 Which element is reduced?

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04/12/2021 4:30 pm

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Palak23

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In the reaction

Cr₂O₇^2- + 14H⁺ + 6I^- → 2Cr³⁺ + 7H₂O + 3I₂

Which element is reduced?

(a) I

(b) O

(d) Cr

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04/12/2021 4:32 pm

Reyana09

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Correct answer: (d) Cr

Explanation:

2I^- → I₂ is oxidation (loss of electrons) ; Cr (+6) changes to Cr (+3) by gain of electrons. Hence Cr is reduced.

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