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In the disproportionation reaction 3HClO3 → HClO4 + Cl2 + 2O2 + H2O, the equivalent mass of the oxidizing agent is

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In the disproportionation reaction

3HClO3 → HClO4 + Cl2 + 2O2 + H2O, the equivalent mass of the oxidizing agent is (molar mass of HClO3 = 84.45)

(a) 16.89

(b) 32.22

(c) 84.45

(d) 28.15

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Correct answer: (a) 16.89

Explanation:

ClO3- → Cl20

x - 6 = -1 x = 0

x = +5  x = 0(x = oxidation number)

Equivalent mass = \(\frac{Molecular\;mass}{Oxidation\;number}\)

= \(\frac{84.45}{5}\) = 16.89

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