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Given Fe^3+ (aq) + e^- → Fe^2+ (aq); Eo = +0.77 V Al^3+ (aq) + 3e^- → Al(s); Eo = -1.66 V Br2(aq) + 2e^- → 2Br^-(aq); Eo = +1.09 V Considering the electrode potentials, which of the following represents the correct order of reducing power?

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Last Post by Reyana09 3 years ago

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04/12/2021 11:41 am

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Palak23

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Given

Fe³⁺ (aq) + e^- → Fe²⁺ (aq); E_o = +0.77 V

Al³⁺ (aq) + 3e^- → Al(s); E_o = -1.66 V

Br₂(aq) + 2e^- → 2Br^-(aq); E_o = +1.09 V

Considering the electrode potentials, which of the following represents the correct order of reducing power?

(a) Fe²⁺ < Al < Br^-

(b) Br^- < Fe²⁺ < Al

(d) Al < Fe²⁺ < Br^-

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1 Answer

04/12/2021 4:06 pm

Reyana09

(@reyana09)

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Correct answer: (d) Al < Fe²⁺ < Br^-

Explanation:

Reducing character decreases down the series. Hence the correct order is Al < Fe²⁺ < Br^-

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Given Fe^3+ (aq) + e^- → Fe^2+ (aq); Eo = +0.77 V Al^3+ (aq) + 3e^- → Al(s); Eo = -1.66 V Br2(aq) + 2e^- → 2Br^-(aq); Eo = +1.09 V Considering the electrode potentials, which of the following represents the correct order of reducing power?

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