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A solution contains Fe^2+, Fe^3+ and I^- ions. This solution was treated with iodine at 35°C. E° for Fe^3+ / Fe^2+ is + 0.77 V and E° for I2 /2I^- = 0.536 V.

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A solution contains Fe2+, Fe3+ and I- ions. This solution was treated with iodine at 35°C. E° for Fe3+ / Fe2+ is + 0.77 V and E° for I2 /2I- = 0.536 V. The favourable redox reaction is :

(a) I2 will be reduced to I-

(b) There will be no redox reaction

(c) I- will be oxidised to I2

(d) Fe2+ will be oxidised to Fe3+

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Correct answer: (c) I- will be oxidised to I2

Explanation:

Given Fe3+/Fe2+ = + 0.77 V

and I2 /2I- = 0.536V

2(e- + Fe3+ → Fe2+)  E° = 0.77 V

2I- → I2 + 2e-       E° = -0.536 V


2Fe3+ + 2I- → 2Fe2+ + I2

E° = E°ok + E°red

= 0.77 - 0.536

= 0.164 V

∴ Since value of E° is + ve reaction will take place.

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