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06/09/2020 10:48 am
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If a cell A with D.P.D. 4 bars is connected to cell B, C, D whose O.P. and T.P. are respectively 4 and 4, 10 and 5 and 7 and 3 bars, the flow of water will be
(a) A and D to B and C
(b) A to B, C and D
(c) B to A, C and D
(d) C to A, B and D
1 Answer
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06/09/2020 10:49 am
(c) B to A, C and D
Explanation:
DPD = OP – TP.
DPD (A) = 4 bar.
DPD (B) = 0 bar.
DPD (C) = 10 – 5 = 5 bars.
DPD (D) = 7 – 3 = 4 bars.
Water always flows from lower DPD (Diffusion Pressure Deficit) to higher DPD. Since the DPD of cell B is the lowest (O) the water will flow from B to A and then to C.