Notifications
Clear all
0
13/09/2021 4:19 pm
Topic starter
The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3 × 10–3 watt will be: (h = 6.6 × 10–34 Js)
(1) 1018
(2) 1017
(3) 1016
(4) 1015
1 Answer
0
13/09/2021 4:24 pm
Answer is (3) 1016
Explanation:
p = \(\frac{nhc}{\lambda}\)
⇒ n = \(\frac{p \lambda}{hc}\)
n = \(\frac{3.3 \times 10^{-3}\times 600 \times 10^{-9}}{6.6 \times 10^{-34}\times 3 \times 10^{8}}\)
= 1016
This post was modified 3 years ago 2 times by admin