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Match Column-I and Column-II and choose the correct match from the given column.. Column-I - Column-II (A) Root mean square speed of gas molecules

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Match the Column-I and Column-II and choose the correct match from the given column.

Column-I   -  Column-II

(A) Root mean square speed of gas molecules → (P) \(\frac{1}{3}\)nmv-2

(B) Pressure exerted by ideal gas → (Q) \(\sqrt{\frac{3RT}{M}}\)

(C) Average kinetic energy of a molecule → (R) \(\frac{5}{2}RT\)

(D) Total internal energy of 1 mole of a diatomic gas  → (R) \(\frac{3}{2}k_BT\)

(1) (A) - (R), (B) - (P), (C) - (S), (D) - (Q)

(2) (A) - (Q), (B) - (R), (C) - (S), (D) - (P)

(3) (A) - (Q), (B) - (P), (C) - (S), (D) - (R)

(4) (A) - (R), (B) - (Q), (C) - (P), (D) - (S)

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Correct answer: (3) (A) - (Q), (B) - (P), (C) - (S), (D) - (R)

Explanation:

Root mean square speed of gas molecules

vrms = \(\sqrt{\frac{3RT}{M}}\)

Pressure exerted by ideal Gas

P = \(\frac{1}{3}\rho v^2_{rms}\)

P = \(\frac{1}{3}mnv^2\)

ρ = mn, v2rms = \(\bar v^2\)

Average kinetic energy of a molecular

KE = \(\frac{3}{2}KT\)

Total internal energy of 1 mole of a diatomic gas

U = \(\frac{f}{2}\mu RT\)

U = \(\frac{5}{2}RT\)(For 1 mole diatomic gas)

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