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In a potentiometer circuit a cell of EMF 1.5 V gives balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire, the balance point occurs?

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In a potentiometer circuit a cell of EMF 1.5 V gives balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire, the balance point occurs?

(1) 60 cm

(2) 21.6 cm

(3) 64 cm

(4) 62 cm

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Answer: (1) 60 cm

Explanation:

\(\frac{E_1}{E_2}\) = \(\frac{ϕ \ell_1}{ϕ \ell_2}\)

\(\frac{1.5}{2.5}\) = \(\frac{36}{\ell_2}\)

⇒ \(\ell_2\) = 36 x \(\frac{5}{3}\) = 60 cm

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