If E and G respectively denote energy and gravitational constant, then E/G has the dimensions of :
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15/09/2021 10:12 am
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If E and G respectively denote energy and gravitational constant, then E/G has the dimensions of :
(1) [M^{2}] [L^{1}] [T^{0}]
(2) [M] [L^{1}] [T ^{1}]
(3) [M] [L^{0}] [T^{0}]
(4) [M^{2}] [L^{2}] [T ^{1}]
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15/09/2021 10:16 am
Correct answer: (1) [M^{2}] [L^{1}] [T^{0}]
Explanation:
E = energy = [ML^{2}T^{2}]
G = Gravitational constant = [M^{1}L^{3}T^{2}]
So \(\frac{E}{G}\) = \(\frac{[E]}{[G]}\)
= \(\frac{ML^2T^{2}}{M^{1}L^3T^{2}}\) = [M^{2}] [L^{1}] [T^{0}]
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